Question 1

Jambmaths question: 

The variance of 3, 2, 3, 6, 2, 4, 4 and 8 is 

Option A: 

6.00

Option B: 

4.00

Option C: 

4.00

Option D: 

3.75

Jamb Maths Solution: 

$\begin{align}  & mean=\bar{x}=\frac{3+2+3+6+2+4+4+8}{8} \\ & mean=\bar{x}=\frac{32}{8}=4 \\ & variance=\frac{\left[ {{(3-4)}^{2}}+{{(2-4)}^{2}}+{{(3-4)}^{2}}+{{(6-4)}^{2}}+{{(2-4)}^{2}}+{{(4-4)}^{2}}+{{(4-4)}^{2}}+{{(8-4)}^{2}} \right]}{8} \\ & variance=\frac{1+4+1+4+4+0+0+16}{8} \\ & \frac{30}{8}=3.75 \\\end{align}$

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