Question 37

waecmaths question: 

Simplify the expression $\frac{{{a}^{2}}{{b}^{4}}-{{b}^{2}}{{a}^{4}}}{ab(a+b)}$

Option A: 

${{a}^{2}}-{{b}^{2}}$

Option B: 

${{b}^{2}}-{{a}^{2}}$

Option C: 

${{a}^{2}}b-a{{b}^{2}}$

Option D: 

$a{{b}^{2}}-{{a}^{2}}b$

waecmaths solution: 

$\begin{align}  & \frac{{{a}^{2}}{{b}^{4}}-{{b}^{2}}{{a}^{4}}}{ab(a+b)}=\frac{{{a}^{2}}{{b}^{2}}({{b}^{2}}-{{a}^{2}})}{ab(a+b)}=\frac{{{(ab)}^{2}}(b-a)(b+a)}{ab(a+b)} \\ & \frac{{{a}^{2}}{{b}^{4}}-{{b}^{2}}{{a}^{4}}}{ab(a+b)}=ab(b-a)=a{{b}^{2}}-{{a}^{2}}b \\\end{align}$ 

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