Question 43

Jambmaths question: 

What is the mean of the data $t,2t-1,t-2,2t-1,4t\text{ and }2t+2$

Option A: 

$2t$

Option B: 

$t-1$

Option C: 

$\tfrac{2}{3}t+1$

Option D: 

$t-\tfrac{1}{3}$

Jamb Maths Solution: 

$\begin{align} & mean=\overline{x}=\frac{t+2t-1+t-2+2t-1+4t+2t+2t+2}{6} \\ & =\frac{12t-2}{6}=2t-\tfrac{1}{3} \end{align}$

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