Question 44

Jambmaths question: 

No.

0

1

2

3

4

5

Frequency

1

4

3

8

2

5

From the table above, find the median and range of the data respectively

Option A: 

(5, 8)

Option B: 

(5,3)

Option C: 

(3, 5)

Option D: 

(8,5)

Jamb Maths Solution: 

Total frequency = 1+ 4 + 3 + 8 + 2 + 5 =23

The median class will be $\tfrac{n+1}{2}th\text{ term}=\tfrac{23+1}{2}th=12th\text{ term}$

From the table, the 12th term will be 3.

While the range is 5 – 0 = 0

(median, range) =(3, 5)

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