Question 47

Jambmaths question: 

In how many ways can the letters of the word ACCEPTANCE be arranged?

Option A: 

$\tfrac{10!}{2!2!3!}$

Option B: 

$\tfrac{10!}{2!3!}$

Option C: 

$\tfrac{10!}{2!2!}$

Option D: 

$10!$

Jamb Maths Solution: 

$\begin{align} & ACCEPTANCE \\ & No\text{ }of\text{ }C=3 \\ & No\text{ }of\text{ }A=2 \\ & No\text{ }of\text{ }E=2 \\ & Acceptance\text{ }has\text{ }10\text{ }letters \\ & Possible\text{ }arrangement\text{ }=\frac{10!}{2!2!3!} \\\end{align}$

Jamb Maths Topic: 
Year of Exam: